Help me.....i have an array of integers......and want to..have four integer at one position in array

hi...

plz help me ....

i have an array of integer.......

eg

int [] array ="23,35,521,615"

in the above array at every position an integer is stored.......as u see.....

now i want another array......of integers....and want to have like this

int[] array2[0] = "2335" ,,array[1] = "521615" means two integers at same position in an new array.....

Visual C#3

"int[] array2[0] = "2335" ,,array[1] = "521615" means two integers at same position in an new array....."

What do you mean by this Can you clarfiy your question please

Best Regards,

Rizwan

hi...

i mean that.........suppose there is a array of integers......

eg...

array[ 0 ] = 21,,,,, array[ 1 ] = 44, ,,, array[ 2 ] = 35 ,,,,,,,array [3] = 22,,,,,array [ 4 ] = 45,,,,array[5] = 23

now above u see at every position there is a integer saved in the array........now i want another array of integers....to be saved like this........

array [ 0 ] = 2144 ,,,,,array [ 1 ] = 3522 ,,,,,,array [ 2 ] = 4523;

so i mean that i want to read and saved 21 and 44 at same array position in a new array .......likewisw 35 and 22 and on same arraay position...............etc...hopefully u now understand it................

why don't you just create a new array and store it down like below:

int[] array2=new int[array.length/2];

for (int a=0;a<array2.length;a++)

array2=Convert.toInt32(array[a*2].toString()+array[(a*2)+1].toString());